(x+1)4=2(2x-3)+2(x-1)

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Solution for (x+1)4=2(2x-3)+2(x-1) equation: 



(x+1)4=2(2x-3)+2(x-1)

We move all terms to the left:

(x+1)4-(2(2x-3)+2(x-1))=0

We multiply parentheses

4x-(2(2x-3)+2(x-1))+4=0



We calculate terms in parentheses: -(2(2x-3)+2(x-1)), so:

2(2x-3)+2(x-1)

We multiply parentheses

4x+2x-6-2

We add all the numbers together, and all the variables

6x-8

Back to the equation:

-(6x-8)



We get rid of parentheses

4x-6x+8+4=0

We add all the numbers together, and all the variables

-2x+12=0

We move all terms containing x to the left, all other terms to the right

-2x=-12

x=-12/-2

x=+6

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