(x+1)=(7x-5)=150

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Solution for (x+1)=(7x-5)=150 equation: 



(x+1)=(7x-5)=150

We move all terms to the left:

(x+1)-((7x-5))=0

We get rid of parentheses

x-((7x-5))+1=0



We calculate terms in parentheses: -((7x-5)), so:

(7x-5)

We get rid of parentheses

7x-5

Back to the equation:

-(7x-5)



We get rid of parentheses

x-7x+5+1=0

We add all the numbers together, and all the variables

-6x+6=0

We move all terms containing x to the left, all other terms to the right

-6x=-6

x=-6/-6

x=1

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