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(x+1.33)(x-5)=0
We multiply parentheses ..
(+x^2-5x+1.33x-6.65)=0
We get rid of parentheses
x^2-5x+1.33x-6.65=0
We add all the numbers together, and all the variables
x^2-3.67x-6.65=0
a = 1; b = -3.67; c = -6.65;
Δ = b2-4ac
Δ = -3.672-4·1·(-6.65)
Δ = 40.0689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.67)-\sqrt{40.0689}}{2*1}=\frac{3.67-\sqrt{40.0689}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.67)+\sqrt{40.0689}}{2*1}=\frac{3.67+\sqrt{40.0689}}{2} $
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