(x+1/x2+5x-14)x=0

Solution for (x+1/x2+5x-14)x=0 equation:

(x+1/x2+5x-14)x=0


Domain of the equation: x2+5x-14)x!=0

x∈R


We add all the numbers together, and all the variables

(6x+1/x2-14)x=0

We multiply parentheses

6x^2+x^2-14x=0

We add all the numbers together, and all the variables

7x^2-14x=0

a = 7; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·7·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*7}=\frac{0}{14}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*7}=\frac{28}{14}
=2
$