(x+10)(x+14)=(x+14)+(x-20)

Solution for (x+10)(x+14)=(x+14)+(x-20) equation:

(x+10)(x+14)=(x+14)+(x-20)

We move all terms to the left:

(x+10)(x+14)-((x+14)+(x-20))=0

We multiply parentheses ..

(+x^2+14x+10x+140)-((x+14)+(x-20))=0


We calculate terms in parentheses: -((x+14)+(x-20)), so:

(x+14)+(x-20)

We get rid of parentheses

x+x+14-20

We add all the numbers together, and all the variables

2x-6

Back to the equation:

-(2x-6)


We get rid of parentheses

x^2+14x+10x-2x+140+6=0

We add all the numbers together, and all the variables

x^2+22x+146=0

a = 1; b = 22; c = +146;
Δ = b2-4ac
Δ = 222-4·1·146
Δ = -100
Delta is less than zero, so there is no solution for the equation