(x+10)(x+14)=(x-14)(x-20)

Solution for (x+10)(x+14)=(x-14)(x-20) equation:

(x+10)(x+14)=(x-14)(x-20)

We move all terms to the left:

(x+10)(x+14)-((x-14)(x-20))=0

We multiply parentheses ..

(+x^2+14x+10x+140)-((x-14)(x-20))=0


We calculate terms in parentheses: -((x-14)(x-20)), so:

(x-14)(x-20)

We multiply parentheses ..

(+x^2-20x-14x+280)

We get rid of parentheses

x^2-20x-14x+280

We add all the numbers together, and all the variables

x^2-34x+280

Back to the equation:

-(x^2-34x+280)


We get rid of parentheses

x^2-x^2+14x+10x+34x+140-280=0

We add all the numbers together, and all the variables

58x-140=0

We move all terms containing x to the left, all other terms to the right

58x=140

x=140/58

x=2+12/29