(x+10)+(2x-40)+(3x-90)=180

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Solution for (x+10)+(2x-40)+(3x-90)=180 equation: 



(x+10)+(2x-40)+(3x-90)=180

We move all terms to the left:

(x+10)+(2x-40)+(3x-90)-(180)=0

We get rid of parentheses

x+2x+3x+10-40-90-180=0

We add all the numbers together, and all the variables

6x-300=0

We move all terms containing x to the left, all other terms to the right

6x=300

x=300/6

x=50

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