(x+10)+(5x+12)=(3x+55)

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Solution for (x+10)+(5x+12)=(3x+55) equation: 



(x+10)+(5x+12)=(3x+55)

We move all terms to the left:

(x+10)+(5x+12)-((3x+55))=0

We get rid of parentheses

x+5x-((3x+55))+10+12=0



We calculate terms in parentheses: -((3x+55)), so:

(3x+55)

We get rid of parentheses

3x+55

Back to the equation:

-(3x+55)



We add all the numbers together, and all the variables

6x-(3x+55)+22=0

We get rid of parentheses

6x-3x-55+22=0

We add all the numbers together, and all the variables

3x-33=0

We move all terms containing x to the left, all other terms to the right

3x=33

x=33/3

x=11

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