(x+10)-5(2x-2)=6(x-2)

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Solution for (x+10)-5(2x-2)=6(x-2) equation: 



(x+10)-5(2x-2)=6(x-2)

We move all terms to the left:

(x+10)-5(2x-2)-(6(x-2))=0

We multiply parentheses

(x+10)-10x-(6(x-2))+10=0

We get rid of parentheses

x-10x-(6(x-2))+10+10=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

-9x-(6x-12)+20=0

We get rid of parentheses

-9x-6x+12+20=0

We add all the numbers together, and all the variables

-15x+32=0

We move all terms containing x to the left, all other terms to the right

-15x=-32

x=-32/-15

x=2+2/15

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