(x+11)(2x+12)=0

Solution for (x+11)(2x+12)=0 equation:

(x+11)(2x+12)=0

We multiply parentheses ..

(+2x^2+12x+22x+132)=0

We get rid of parentheses

2x^2+12x+22x+132=0

We add all the numbers together, and all the variables

2x^2+34x+132=0

a = 2; b = 34; c = +132;
Δ = b2-4ac
Δ = 342-4·2·132
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-10}{2*2}=\frac{-44}{4}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+10}{2*2}=\frac{-24}{4}
=-6
$