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(x+11)(x+23)=589
We move all terms to the left:
(x+11)(x+23)-(589)=0
We multiply parentheses ..
(+x^2+23x+11x+253)-589=0
We get rid of parentheses
x^2+23x+11x+253-589=0
We add all the numbers together, and all the variables
x^2+34x-336=0
a = 1; b = 34; c = -336;
Δ = b2-4ac
Δ = 342-4·1·(-336)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-50}{2*1}=\frac{-84}{2} =-42 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+50}{2*1}=\frac{16}{2} =8 $
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