(x+12)(x+10)=0

Solution for (x+12)(x+10)=0 equation:

(x+12)(x+10)=0

We multiply parentheses ..

(+x^2+10x+12x+120)=0

We get rid of parentheses

x^2+10x+12x+120=0

We add all the numbers together, and all the variables

x^2+22x+120=0

a = 1; b = 22; c = +120;
Δ = b2-4ac
Δ = 222-4·1·120
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2}{2*1}=\frac{-24}{2}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2}{2*1}=\frac{-20}{2}
=-10
$