(x+12)+(2x-36)+(1/3+44)=0

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Solution for (x+12)+(2x-36)+(1/3+44)=0 equation: 



(x+12)+(2x-36)+(1/3+44)=0

We get rid of parentheses

x+2x+12-36+44+1/3=0

We multiply all the terms by the denominator


x*3+2x*3+1+12*3-36*3+44*3=0

We add all the numbers together, and all the variables

x*3+2x*3+61=0

Wy multiply elements

3x+6x+61=0

We add all the numbers together, and all the variables

9x+61=0

We move all terms containing x to the left, all other terms to the right

9x=-61

x=-61/9

x=-6+7/9

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