(x+12)/(x-3)+1=(15)/(x-3)

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Solution for (x+12)/(x-3)+1=(15)/(x-3) equation: 


D( x )

x-3 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:3) U (3:+oo)

(x+12)/(x-3)+1 = 15/(x-3) // - 15/(x-3)

(x+12)/(x-3)-(15/(x-3))+1 = 0

(x+12)/(x-3)-15*(x-3)^-1+1 = 0

(x+12)/(x-3)-15/(x-3)+1 = 0

(x+12)/(x-3)-15/(x-3)+(1*(x-3))/(x-3) = 0

1*(x-3)+x-15+12 = 0

x+x-3-3 = 0

2*x-6 = 0

(2*x-6)/(x-3) = 0

(2*x-6)/(x-3) = 0 // * x-3

2*x-6 = 0

2*x-6 = 0 // + 6

2*x = 6 // : 2

x = 6/2

x = 3

x in { 3} 

x belongs to the empty set

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