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(x+13)(3x-7)=0
We multiply parentheses ..
(+3x^2-7x+39x-91)=0
We get rid of parentheses
3x^2-7x+39x-91=0
We add all the numbers together, and all the variables
3x^2+32x-91=0
a = 3; b = 32; c = -91;
Δ = b2-4ac
Δ = 322-4·3·(-91)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-46}{2*3}=\frac{-78}{6} =-13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+46}{2*3}=\frac{14}{6} =2+1/3 $
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