(x+13)(x+3)=2

Solution for (x+13)(x+3)=2 equation:

(x+13)(x+3)=2

We move all terms to the left:

(x+13)(x+3)-(2)=0

We multiply parentheses ..

(+x^2+3x+13x+39)-2=0

We get rid of parentheses

x^2+3x+13x+39-2=0

We add all the numbers together, and all the variables

x^2+16x+37=0

a = 1; b = 16; c = +37;
Δ = b2-4ac
Δ = 162-4·1·37
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-6\sqrt{3}}{2*1}=\frac{-16-6\sqrt{3}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+6\sqrt{3}}{2*1}=\frac{-16+6\sqrt{3}}{2}
$