(x+13)+(3x+1)=(5x-2)

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Solution for (x+13)+(3x+1)=(5x-2) equation: 



(x+13)+(3x+1)=(5x-2)

We move all terms to the left:

(x+13)+(3x+1)-((5x-2))=0

We get rid of parentheses

x+3x-((5x-2))+13+1=0



We calculate terms in parentheses: -((5x-2)), so:

(5x-2)

We get rid of parentheses

5x-2

Back to the equation:

-(5x-2)



We add all the numbers together, and all the variables

4x-(5x-2)+14=0

We get rid of parentheses

4x-5x+2+14=0

We add all the numbers together, and all the variables

-1x+16=0

We move all terms containing x to the left, all other terms to the right

-x=-16

x=-16/-1

x=+16

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