(x+13)+(4x-3)+(9x-22)=58

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Solution for (x+13)+(4x-3)+(9x-22)=58 equation: 



(x+13)+(4x-3)+(9x-22)=58

We move all terms to the left:

(x+13)+(4x-3)+(9x-22)-(58)=0

We get rid of parentheses

x+4x+9x+13-3-22-58=0

We add all the numbers together, and all the variables

14x-70=0

We move all terms containing x to the left, all other terms to the right

14x=70

x=70/14

x=5

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