(x+14)(x+14)=256

Solution for (x+14)(x+14)=256 equation:

(x+14)(x+14)=256

We move all terms to the left:

(x+14)(x+14)-(256)=0

We multiply parentheses ..

(+x^2+14x+14x+196)-256=0

We get rid of parentheses

x^2+14x+14x+196-256=0

We add all the numbers together, and all the variables

x^2+28x-60=0

a = 1; b = 28; c = -60;
Δ = b2-4ac
Δ = 282-4·1·(-60)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-32}{2*1}=\frac{-60}{2}
=-30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+32}{2*1}=\frac{4}{2}
=2
$