(x+15)(x)=1350

Solution for (x+15)(x)=1350 equation:

(x+15)(x)=1350

We move all terms to the left:

(x+15)(x)-(1350)=0

We multiply parentheses

x^2+15x-1350=0

a = 1; b = 15; c = -1350;
Δ = b2-4ac
Δ = 152-4·1·(-1350)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-75}{2*1}=\frac{-90}{2}
=-45
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+75}{2*1}=\frac{60}{2}
=30
$