(x+15)+(3x-5)=120

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Solution for (x+15)+(3x-5)=120 equation:



(x+15)+(3x-5)=120
We move all terms to the left:
(x+15)+(3x-5)-(120)=0
We get rid of parentheses
x+3x+15-5-120=0
We add all the numbers together, and all the variables
4x-110=0
We move all terms containing x to the left, all other terms to the right
4x=110
x=110/4
x=27+1/2

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