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(x+15)+(4x-7)=59
We move all terms to the left:
(x+15)+(4x-7)-(59)=0
We get rid of parentheses
x+4x+15-7-59=0
We add all the numbers together, and all the variables
5x-51=0
We move all terms containing x to the left, all other terms to the right
5x=51
x=51/5
x=10+1/5
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