(x+15)+106+(2x-35)+(x-10)=360

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Solution for (x+15)+106+(2x-35)+(x-10)=360 equation: 



(x+15)+106+(2x-35)+(x-10)=360

We move all terms to the left:

(x+15)+106+(2x-35)+(x-10)-(360)=0

We add all the numbers together, and all the variables

(x+15)+(2x-35)+(x-10)-254=0

We get rid of parentheses

x+2x+x+15-35-10-254=0

We add all the numbers together, and all the variables

4x-284=0

We move all terms containing x to the left, all other terms to the right

4x=284

x=284/4

x=71

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