(x+15)/(x+4)+1=(11/x+4)

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Solution for (x+15)/(x+4)+1=(11/x+4) equation: 


D( x )

x+4 = 0

x = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x = 0

x = 0

x in (-oo:-4) U (-4:0) U (0:+oo)

(x+15)/(x+4)+1 = 11/x+4 // - 11/x+4

(x+15)/(x+4)-(11/x)-4+1 = 0

(x+15)/(x+4)-11*x^-1-4+1 = 0

(x+15)/(x+4)-11/x-4+1 = 0

(x*(x+15))/(x*(x+4))+(-11*(x+4))/(x*(x+4))+(-4*x*(x+4))/(x*(x+4))+(1*x*(x+4))/(x*(x+4)) = 0

x*(x+15)-11*(x+4)-4*x*(x+4)+1*x*(x+4) = 0

x^2-4*x^2+x^2+4*x-16*x+4*x-44 = 0

x^2-3*x^2-12*x+4*x-44 = 0

-2*x^2-8*x-44 = 0

-2*x^2-8*x-44 = 0

-2*(x^2+4*x+22) = 0

x^2+4*x+22 = 0

DELTA = 4^2-(1*4*22)

DELTA = -72

DELTA < 0

-2 = 0

-2/(x*(x+4)) = 0

-2/(x*(x+4)) = 0 // * x*(x+4)

-2 = 0

x belongs to the empty set

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