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(x+16)(x+13)=0
We multiply parentheses ..
(+x^2+13x+16x+208)=0
We get rid of parentheses
x^2+13x+16x+208=0
We add all the numbers together, and all the variables
x^2+29x+208=0
a = 1; b = 29; c = +208;
Δ = b2-4ac
Δ = 292-4·1·208
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-3}{2*1}=\frac{-32}{2} =-16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+3}{2*1}=\frac{-26}{2} =-13 $
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