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(x+16)(x+13)=270
We move all terms to the left:
(x+16)(x+13)-(270)=0
We multiply parentheses ..
(+x^2+13x+16x+208)-270=0
We get rid of parentheses
x^2+13x+16x+208-270=0
We add all the numbers together, and all the variables
x^2+29x-62=0
a = 1; b = 29; c = -62;
Δ = b2-4ac
Δ = 292-4·1·(-62)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-33}{2*1}=\frac{-62}{2} =-31 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+33}{2*1}=\frac{4}{2} =2 $
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