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(x+16)(x+16)=400
We move all terms to the left:
(x+16)(x+16)-(400)=0
We multiply parentheses ..
(+x^2+16x+16x+256)-400=0
We get rid of parentheses
x^2+16x+16x+256-400=0
We add all the numbers together, and all the variables
x^2+32x-144=0
a = 1; b = 32; c = -144;
Δ = b2-4ac
Δ = 322-4·1·(-144)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-40}{2*1}=\frac{-72}{2} =-36 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+40}{2*1}=\frac{8}{2} =4 $
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