(x+16)(x-22)=0

Solution for (x+16)(x-22)=0 equation:

(x+16)(x-22)=0

We multiply parentheses ..

(+x^2-22x+16x-352)=0

We get rid of parentheses

x^2-22x+16x-352=0

We add all the numbers together, and all the variables

x^2-6x-352=0

a = 1; b = -6; c = -352;
Δ = b2-4ac
Δ = -62-4·1·(-352)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-38}{2*1}=\frac{-32}{2}
=-16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+38}{2*1}=\frac{44}{2}
=22
$