(x+17)/(3)-(20-x)/(2)=(5x-28)/(2)+9

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Solution for (x+17)/(3)-(20-x)/(2)=(5x-28)/(2)+9 equation: 



(x+17)/(3)-(20-x)/(2)=(5x-28)/(2)+9

We move all terms to the left:

(x+17)/(3)-(20-x)/(2)-((5x-28)/(2)+9)=0

We add all the numbers together, and all the variables

(x+17)/3-(-1x+20)/2-((5x-28)/2+9)=0

We calculate fractions


((x+17)*2*2)/()+(3x-60)/()+(-((5x-28)*3)/()=0



We calculate terms in parentheses: +((x+17)*2*2)/(), so:

(x+17)*2*2)/(

We multiply all the terms by the denominator


(x+17)*2*2)

We get rid of parentheses

x+17)*2*2

We add all the numbers together, and all the variables

x

Back to the equation:

+(x)





We calculate terms in parentheses: +(-((5x-28)*3)/(), so:

-((5x-28)*3)/(

We multiply all the terms by the denominator


-((5x-28)*3)



We calculate terms in parentheses: -((5x-28)*3), so:

(5x-28)*3

We multiply parentheses

15x-84

Back to the equation:

-(15x-84)



We get rid of parentheses

-15x+84

Back to the equation:

+(-15x+84)



We get rid of parentheses

x+(3x-60)/()-15x+84=0

We multiply all the terms by the denominator


x*()+(3x-60)-15x*()+84*()=0

We add all the numbers together, and all the variables

x*()+(3x-60)-15x*()=0

We get rid of parentheses

x*()+3x-15x*()-60=0

We add all the numbers together, and all the variables

3x+x*()-15x*()-60=0

We move all terms containing x to the left, all other terms to the right

3x+x*()-15x*()=60

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