(x+19)(19x)=0

Solution for (x+19)(19x)=0 equation:

(x+19)(19x)=0

We multiply parentheses

19x^2+361x=0

a = 19; b = 361; c = 0;
Δ = b2-4ac
Δ = 3612-4·19·0
Δ = 130321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{130321}=361$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(361)-361}{2*19}=\frac{-722}{38}
=-19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(361)+361}{2*19}=\frac{0}{38}
=0
$