(x+19)+(x+1)+x=68

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Solution for (x+19)+(x+1)+x=68 equation: 



(x+19)+(x+1)+x=68

We move all terms to the left:

(x+19)+(x+1)+x-(68)=0

We add all the numbers together, and all the variables

x+(x+19)+(x+1)-68=0

We get rid of parentheses

x+x+x+19+1-68=0

We add all the numbers together, and all the variables

3x-48=0

We move all terms containing x to the left, all other terms to the right

3x=48

x=48/3

x=16

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