(x+2)(1/x+2+5)=(x+2)(21/x+2)

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Solution for (x+2)(1/x+2+5)=(x+2)(21/x+2) equation: 



(x+2)(1/x+2+5)=(x+2)(21/x+2)

We move all terms to the left:

(x+2)(1/x+2+5)-((x+2)(21/x+2))=0



Domain of the equation: x+2+5)!=0

We move all terms containing x to the left, all other terms to the right

x+5)!=-2

x∈R





Domain of the equation: x+2))!=0

x∈R



We add all the numbers together, and all the variables

(x+2)(1/x+7)-((x+2)(21/x+2))=0

We multiply parentheses ..

(+x^2+7x+2x+14)-((x+2)(21/x+2))=0

We multiply all the terms by the denominator


((+x^2+7x+2x+14))*x+2))-((x+2)(21=0

We add all the numbers together, and all the variables

((+x^2+7x+2x+14))*x+2))-((x=0

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