(x+2)(2x-3)f(0)=7

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Solution for (x+2)(2x-3)f(0)=7 equation: 


Simplifying
(x + 2)(2x + -3) * f(0) = 7

Reorder the terms:
(2 + x)(2x + -3) * f(0) = 7

Reorder the terms:
(2 + x)(-3 + 2x) * f(0) = 7

Reorder the terms for easier multiplication:
0f(2 + x)(-3 + 2x) = 7

Anything times zero is zero.
0f(2 + x)(-3 + 2x) = 7

Solving
0 = 7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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