(x+2)(3x+4)(3x+7)(x+3)=2600

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Solution for (x+2)(3x+4)(3x+7)(x+3)=2600 equation: 



(x+2)(3x+4)(3x+7)(x+3)=2600

We move all terms to the left:

(x+2)(3x+4)(3x+7)(x+3)-(2600)=0

We multiply parentheses ..

(+3x^2+4x+6x+8)(3x+7)(x+3)-2600=0

We multiply parentheses ..

(+3x^2+4x+6x+8)(+3x^2+9x+7x+21)-2600=0

We move all terms containing x to the left, all other terms to the right

(+3x^2+4x+6x+8)(+3x^2+9x+7x+21)=2600

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