(x+2)(x)=86

Solution for (x+2)(x)=86 equation:

(x+2)(x)=86

We move all terms to the left:

(x+2)(x)-(86)=0

We multiply parentheses

x^2+2x-86=0

a = 1; b = 2; c = -86;
Δ = b2-4ac
Δ = 22-4·1·(-86)
Δ = 348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{348}=\sqrt{4*87}=\sqrt{4}*\sqrt{87}=2\sqrt{87}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{87}}{2*1}=\frac{-2-2\sqrt{87}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{87}}{2*1}=\frac{-2+2\sqrt{87}}{2}
$