(x+2)(x*x+4x+4)-x-2=(x+1)(x+2)(x+3)

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Solution for (x+2)(x*x+4x+4)-x-2=(x+1)(x+2)(x+3) equation: 



(x+2)(x*x+4x+4)-x-2=(x+1)(x+2)(x+3)

We move all terms to the left:

(x+2)(x*x+4x+4)-x-2-((x+1)(x+2)(x+3))=0

We add all the numbers together, and all the variables

(x+2)(4x+x*x+4)-x-((x+1)(x+2)(x+3))-2=0

We add all the numbers together, and all the variables

-1x+(x+2)(4x+x*x+4)-((x+1)(x+2)(x+3))-2=0

We multiply parentheses ..

(+4x^2+x^3+4x+8x+2x^2+8)-1x-((x+1)(x+2)(x+3))-2=0



We calculate terms in parentheses: -((x+1)(x+2)(x+3)), so:

(x+1)(x+2)(x+3)

We multiply parentheses ..

(+x^2+2x+x+2)(x+3)

Back to the equation:

-((+x^2+2x+x+2)(x+3))



We do not support expression: x^3

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