(x+2)(x+1)/x-4=0

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Solution for (x+2)(x+1)/x-4=0 equation: 



(x+2)(x+1)/x-4=0



Domain of the equation: x!=0

x∈R



We multiply parentheses ..

(+x^2+x+2x+2)/x-4=0

We multiply all the terms by the denominator


(+x^2+x+2x+2)-4*x=0

We add all the numbers together, and all the variables

(+x^2+x+2x+2)-4x=0

We get rid of parentheses

x^2+x+2x-4x+2=0

We add all the numbers together, and all the variables

x^2-1x+2=0

a = 1; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·1·2
Δ = -7
Delta is less than zero, so there is no solution for the equation

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