(x+2)(x+1)=272

Solution for (x+2)(x+1)=272 equation:

(x+2)(x+1)=272

We move all terms to the left:

(x+2)(x+1)-(272)=0

We multiply parentheses ..

(+x^2+x+2x+2)-272=0

We get rid of parentheses

x^2+x+2x+2-272=0

We add all the numbers together, and all the variables

x^2+3x-270=0

a = 1; b = 3; c = -270;
Δ = b2-4ac
Δ = 32-4·1·(-270)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-33}{2*1}=\frac{-36}{2}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+33}{2*1}=\frac{30}{2}
=15
$