(x+2)(x+2)+2=x(x)-x-4

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Solution for (x+2)(x+2)+2=x(x)-x-4 equation: 



(x+2)(x+2)+2=x(x)-x-4

We move all terms to the left:

(x+2)(x+2)+2-(x(x)-x-4)=0

We add all the numbers together, and all the variables

(x+2)(x+2)-(-1x+xx-4)+2=0

We get rid of parentheses

(x+2)(x+2)+1x-xx+4+2=0

We multiply parentheses ..

(+x^2+2x+2x+4)+1x-xx+4+2=0

We add all the numbers together, and all the variables

(+x^2+2x+2x+4)+x-xx+6=0

We get rid of parentheses

x^2+2x+2x+x-xx+4+6=0

We add all the numbers together, and all the variables

x^2+5x-xx+10=0

We move all terms containing x to the left, all other terms to the right

x^2+5x-xx=-10

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