(x+2)(x+2)+4=0

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Solution for (x+2)(x+2)+4=0 equation:


Simplifying
(x + 2)(x + 2) + 4 = 0

Reorder the terms:
(2 + x)(x + 2) + 4 = 0

Reorder the terms:
(2 + x)(2 + x) + 4 = 0

Multiply (2 + x) * (2 + x)
(2(2 + x) + x(2 + x)) + 4 = 0
((2 * 2 + x * 2) + x(2 + x)) + 4 = 0
((4 + 2x) + x(2 + x)) + 4 = 0
(4 + 2x + (2 * x + x * x)) + 4 = 0
(4 + 2x + (2x + x2)) + 4 = 0

Combine like terms: 2x + 2x = 4x
(4 + 4x + x2) + 4 = 0

Reorder the terms:
4 + 4 + 4x + x2 = 0

Combine like terms: 4 + 4 = 8
8 + 4x + x2 = 0

Solving
8 + 4x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-8' to each side of the equation.
8 + 4x + -8 + x2 = 0 + -8

Reorder the terms:
8 + -8 + 4x + x2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + 4x + x2 = 0 + -8
4x + x2 = 0 + -8

Combine like terms: 0 + -8 = -8
4x + x2 = -8

The x term is 4x.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4x + 4 + x2 = -8 + 4

Reorder the terms:
4 + 4x + x2 = -8 + 4

Combine like terms: -8 + 4 = -4
4 + 4x + x2 = -4

Factor a perfect square on the left side:
(x + 2)(x + 2) = -4

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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