(x+2)(x+2)-1=35

Solution for (x+2)(x+2)-1=35 equation:

(x+2)(x+2)-1=35

We move all terms to the left:

(x+2)(x+2)-1-(35)=0

We add all the numbers together, and all the variables

(x+2)(x+2)-36=0

We multiply parentheses ..

(+x^2+2x+2x+4)-36=0

We get rid of parentheses

x^2+2x+2x+4-36=0

We add all the numbers together, and all the variables

x^2+4x-32=0

a = 1; b = 4; c = -32;
Δ = b2-4ac
Δ = 42-4·1·(-32)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-12}{2*1}=\frac{-16}{2}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+12}{2*1}=\frac{8}{2}
=4
$