(x+2)(x+2)=81+(x+1)(x+1)

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Solution for (x+2)(x+2)=81+(x+1)(x+1) equation: 



(x+2)(x+2)=81+(x+1)(x+1)

We move all terms to the left:

(x+2)(x+2)-(81+(x+1)(x+1))=0

We multiply parentheses ..

(+x^2+2x+2x+4)-(81+(x+1)(x+1))=0



We calculate terms in parentheses: -(81+(x+1)(x+1)), so:

81+(x+1)(x+1)

determiningTheFunctionDomain
(x+1)(x+1)+81

We multiply parentheses ..

(+x^2+x+x+1)+81

We get rid of parentheses

x^2+x+x+1+81

We add all the numbers together, and all the variables

x^2+2x+82

Back to the equation:

-(x^2+2x+82)



We get rid of parentheses

x^2-x^2+2x+2x-2x+4-82=0

We add all the numbers together, and all the variables

2x-78=0

We move all terms containing x to the left, all other terms to the right

2x=78

x=78/2

x=39

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