(x+2)(x+3)(x+4)(x+5)=360

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Solution for (x+2)(x+3)(x+4)(x+5)=360 equation:



(x+2)(x+3)(x+4)(x+5)=360
We move all terms to the left:
(x+2)(x+3)(x+4)(x+5)-(360)=0
We multiply parentheses ..
(+x^2+3x+2x+6)(x+4)(x+5)-360=0
We multiply parentheses ..
(+x^2+3x+2x+6)(+x^2+5x+4x+20)-360=0
We move all terms containing x to the left, all other terms to the right
(+x^2+3x+2x+6)(+x^2+5x+4x+20)=360

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