(x+2)(x+3)(x-3)(x-2)-2x(x+1)=0

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Solution for (x+2)(x+3)(x-3)(x-2)-2x(x+1)=0 equation: 



(x+2)(x+3)(x-3)(x-2)-2x(x+1)=0

We multiply parentheses

-2x^2+(x+2)(x+3)(x-3)(x-2)-2x=0

We multiply parentheses ..

-2x^2+(+x^2+3x+2x+6)(x-3)(x-2)-2x=0

We multiply parentheses ..

-2x^2+(+x^2+3x+2x+6)(+x^2-2x-3x+6)-2x=0

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