(x+2)(x+3)(x-4)(x-5)-44=0

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Solution for (x+2)(x+3)(x-4)(x-5)-44=0 equation: 



(x+2)(x+3)(x-4)(x-5)-44=0

We multiply parentheses ..

(+x^2+3x+2x+6)(x-4)(x-5)-44=0

We multiply parentheses ..

(+x^2+3x+2x+6)(+x^2-5x-4x+20)-44=0

We move all terms containing x to the left, all other terms to the right

(+x^2+3x+2x+6)(+x^2-5x-4x+20)=44

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