(x+2)(x+3)+(x-3(x-2)-2x(x+1)=0

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Solution for (x+2)(x+3)+(x-3(x-2)-2x(x+1)=0 equation: 



(x+2)(x+3)+(x-3(x-2)-2x(x+1)=0

We multiply parentheses ..

(+x^2+3x+2x+6)+(x-3(x-2)-2x(x+1)=0



We calculate terms in parentheses: +(x-3(x-2)-2x(x+1), so:

x-3(x-2)-2x(x+1

We multiply parentheses

x-3x-2x(x+1+6

We add all the numbers together, and all the variables

-2x-2x(x+1+6

Back to the equation:

+(-2x-2x(x+1+6)



We add all the numbers together, and all the variables

(+x^2+3x+2x+6)+(-2x-2x(x+7)=0

We get rid of parentheses

x^2+3x+2x+(-2x-2x(x+7)+6=0

We add all the numbers together, and all the variables

x^2+5x+(-2x-2x(x+7)+6=0

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