(x+2)(x+3)+(x-3)(x-2)-2x(x+1=0

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Solution for (x+2)(x+3)+(x-3)(x-2)-2x(x+1=0 equation: 



(x+2)(x+3)+(x-3)(x-2)-2x(x+1=0

We multiply parentheses ..

(+x^2+3x+2x+6)+(x-3)(x-2)-2x(x+1=0

We get rid of parentheses

x^2+3x+2x+(x-3)(x-2)-2x(x+1+6=0

We multiply parentheses ..

x^2+(+x^2-2x-3x+6)+3x+2x-2x(x+1+6=0

We add all the numbers together, and all the variables

x^2+(+x^2-2x-3x+6)+5x-2x(x+1+6=0

We get rid of parentheses

x^2+x^2-2x-3x+5x-2x(x+1+6+6=0

We add all the numbers together, and all the variables

2x^2-2x(x+1+6+6=0

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