(x+2)(x+3)+(x-3)+x-2)-2x(x+1)=0

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Solution for (x+2)(x+3)+(x-3)+x-2)-2x(x+1)=0 equation:



(x+2)(x+3)+(x-3)+x-2)-2x(x+1)=0
We add all the numbers together, and all the variables
x+(x+2)(x+3)+(x-3)-2)-2x(x=0
We get rid of parentheses
x+(x+2)(x+3)+x-2)-2x(x-3=0
We multiply parentheses ..
(+x^2+3x+2x+6)+x+x-2)-2x(x-3=0
We add all the numbers together, and all the variables
(+x^2+3x+2x+6)+2x-2)-2x(x-3=0
We get rid of parentheses
x^2+3x+2x+2x-2)-2x(x+6-3=0
We add all the numbers together, and all the variables
x^2+7x-2)-2x(x+3=0
We move all terms containing x to the left, all other terms to the right
x^2+7x-2)-2x(x=-3

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