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(x+2)(x+3)-(x+2)(x-3)=0
We multiply parentheses ..
(+x^2+3x+2x+6)-(x+2)(x-3)=0
We get rid of parentheses
x^2+3x+2x-(x+2)(x-3)+6=0
We multiply parentheses ..
x^2-(+x^2-3x+2x-6)+3x+2x+6=0
We add all the numbers together, and all the variables
x^2-(+x^2-3x+2x-6)+5x+6=0
We get rid of parentheses
x^2-x^2+3x-2x+5x+6+6=0
We add all the numbers together, and all the variables
6x+12=0
We move all terms containing x to the left, all other terms to the right
6x=-12
x=-12/6
x=-2
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