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(x+2)(x+3)-(x-2)(x-5)=0
We multiply parentheses ..
(+x^2+3x+2x+6)-(x-2)(x-5)=0
We get rid of parentheses
x^2+3x+2x-(x-2)(x-5)+6=0
We multiply parentheses ..
x^2-(+x^2-5x-2x+10)+3x+2x+6=0
We add all the numbers together, and all the variables
x^2-(+x^2-5x-2x+10)+5x+6=0
We get rid of parentheses
x^2-x^2+5x+2x+5x-10+6=0
We add all the numbers together, and all the variables
12x-4=0
We move all terms containing x to the left, all other terms to the right
12x=4
x=4/12
x=1/3
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